How do I remove the new ObjectId() from my output when displaying JSON data?
Below is my code to get the data using the id from mongodb:
async get(id) {
if (!id) throw 'You must provide an id to search for';
const restaurantsCollection = await restaurants();
const res = await restaurantsCollection.findOne({ _id: id });
if (res === null) throw 'No restaurant with that id';
return res;
The output is:
{
_id: new ObjectId("6157530bbba1dbb9f7e68e4a"),
name: 'The Saffron Lounge',
location: 'New York City, New York',
phoneNumber: '123-456-7890',
website: 'http://www.saffronlounge.com',
priceRange: '$$$$',
cuisines: [ 'Cuban', 'Italian' ],
overallRating: 3,
serviceOptions: { dineIn: true, takeOut: true, delivery: false }
}
The output I want is:
{
_id: "6157530bbba1dbb9f7e68e4a",
name: 'The Saffron Lounge',
location: 'New York City, New York',
phoneNumber: '123-456-7890',
website: 'http://www.saffronlounge.com',
priceRange: '$$$$',
cuisines: [ 'Cuban', 'Italian' ],
overallRating: 3,
serviceOptions: { dineIn: true, takeOut: true, delivery: false }
}
Do I use ObjectId.toString()? Not sure where to use this either
According to this https://docs.mongodb.com/manual/reference/method/ObjectId.toString/ ObjectId.toString() will give you a string that still contains the ObjectId("...") part. You could use a regex to remove that.
async get(id) {
if (!id) throw 'You must provide an id to search for';
const restaurantsCollection = await restaurants();
const res = await restaurantsCollection.findOne({ _id: id });
if (res === null) throw 'No restaurant with that id';
res._id = res._id.toString().replace(/ObjectId\("(.*)"\)/, "$1")
return res;
}res._id = res._id.str;
return res;