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ViewsRegex to match the data between the double quotes
I have below strings
1. "Settings Icon": "xxhdjxxx7wn"
2. "Settings Icon": "afewfwl"
3. "Settings Icon": "fdj ssde"
I want the regex to match all these strings by ignoring the content in right side of colon
I have (['"])(?:(?!\1|\\).|\\.)*\1 which matches with content inside double quote. But couldn't solve above case.. Please help
·
Juan Pablo Isaza
2 answers
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If I understand you're question correctly, you only want the string within the quotes, from the left side of the colon. Is that correct? If so, this might work for you:
(['"])([^\1]*?)\1:.*$
For this expression, capture group 2 will give you what you want.
·
Juan Pablo Isaza
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Use
const string = `1. "Settings Icon": "xxhdjxxx7wn"
2. "Settings Icon": "afewfwl"
3. "Settings Icon": "fdj ssde"`
console.log( string.match(/(?<=")[^"]+(?=":)/g) )DEMO
EXPLANATION
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(?<= look behind to see if there is:
--------------------------------------------------------------------------------
" '"'
--------------------------------------------------------------------------------
) end of look-behind
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[^"]+ any character except: '"' (1 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
(?= look ahead to see if there is:
--------------------------------------------------------------------------------
": '":'
--------------------------------------------------------------------------------
) end of look-ahead
See regex proof.
·
Juan Pablo Isaza
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