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unable to change the items based on id and expected result should be in output format

unable to change the items based on id and expected result should be in output format

const items = [
        { id: 1, value: "first" },
        { id: 2, value: "second" },
        { id: 3, value: "third" }
      ];
      const expectedOutput = [
{ id: 1, value: "first" },
        { id: 2, value: "newvalue" },
        { id: 3, value: "third" }
]
      function getData(value, id) {
       return items.map((_each)=> {
         if(_each.id === id) {
           //need to update items with id=2
         }
       })
      }
      
      console.log(getData("newvalue", 2))

about 4 years ago · Juan Pablo Isaza
2 answers
Answer question

0

let inputArr = {
  "data": [{
      "id": 1,
      "value": "first",
      "row": "A"
    },
    {
      "id": 2,
      "value": "second",
      "row": "A"
    },
    {
      "id": 3,
      "value": "Third",
      "row": "B"
    },
    {
      "id": 4,
      "value": "Fourth",
      "row": "B"
    }
  ]
}

function format(inputArr) {
  let arr = []
  let obj = {};
  inputArr.data.forEach(el => {
    obj = {
      ...obj,
      [el.row]: [...(obj[el.row] || []) , el.value],
    }

  });
  arr.push(obj);
  return arr;
}
let outputArr = format(inputArr)
console.log(outputArr)

let expectedOutput = [{
  "A": ["first", "second"]
}, {
  "B": ["Third", "Fourth"]
}]

about 4 years ago · Juan Pablo Isaza Report

0

@chidananda, Map callback should return updated item. Minor modification to your code would work!

const items = [
        { id: 1, value: "first" },
        { id: 2, value: "second" },
        { id: 3, value: "third" }
      ];
      const expectedOutput = [
{ id: 1, value: "first" },
        { id: 2, value: "newvalue" },
        { id: 3, value: "third" }
]
      function getData(value, id) {
       return items.map((_each)=> {
         if(_each.id === id) {
           _each.value = value;
         }
         return _each; // Return the modified item
       })
      }
      
      console.log(getData("newvalue", 2))

about 4 years ago · Juan Pablo Isaza Report
Answer question
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