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How to fetch items one by one from firebase database?

How can I add only one element to the page that I have added? Now, every time I add a bank, the entire database is pulled out and those banks that have already been added are drawn again.

const sendBankData = () => {
  set(ref(database, "banks/" + bankName.value), {
    bankName: bankName.value,
    interestRate: interestRate.value,
    maximumLoan: maximumLoan.value,
    minimumDownPayment: minimumDownPayment.value,
    loanTerm: loanTerm.value,
  })
    .then(() => {
      successfulPopUp();
    })
    .catch((error) => {
      // errorPopUp();
    });
};

const getBanksFunc = () => {
  const bankRef = ref(database, "banks/");
  onValue(bankRef, (snapshot) => {
    const data = snapshot.val();
    displayBanks(data);
  });
};

about 4 years ago · Juan Pablo Isaza
2 answers
Answer question

0

Haven't used Firebase in a long time but if I remember correctly you'd pass the ID of the bank into the ref (const bankRef = ref(database, "banks/ID-OF-THE-BANK");

or you could sort and limit by create date.

about 4 years ago · Juan Pablo Isaza Report

0

As commented above mentioned. You need to pass the ID to get the document you just inserted.

So for that you have two options:

One is to set a custom document Id and get the id you just inserted. Or get the doc id with the reference:

const sendBankData = () => {
  set(ref(database, "banks/" + bankName.value), {
    bankName: bankName.value,
    interestRate: interestRate.value,
    maximumLoan: maximumLoan.value,
    minimumDownPayment: minimumDownPayment.value,
    loanTerm: loanTerm.value,
  })
    .then((docRef) => {
      console.log("Document written with ID: ", docRef.id); // Right here you have the if in the of the document you're looking for.

      successfulPopUp();
      // Then you can do the call to get the document:
      const bankRef = ref(database, "banks/${docRef.id}");
           onValue(bankRef, (snapshot) => {
             const data = snapshot.val();
             displayBanks(data);
       });

    })
    .catch((error) => {
      // errorPopUp();
    });
};
about 4 years ago · Juan Pablo Isaza Report
Answer question
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