i am trying to find the name with the lowest number after it, but iterating over it is slow with larger lists. For exaple the expected output should be ["bob", 1] ["jeff", 2] ["wal-E",2]
let items = [["bob",1],["jeff",2],["wal-E",2],["bob",1],["bob",10]]
let items2 = []
let Lowest = 0;
for (y in items){
for (z in items)
{
if (items[y][0] == items[z][0] && items[y][1]<=items[z][1]){
continue;
} else if (items[y][0] == items[z][0]){
Lowest += 1
if (Lowest >= 2){
break;
}
else {
continue;
}
}
}
if (Lowest == 0){
items2.push(items[y])
}
}
console.log(items2);You could reduce the array and collect the smallest values.
const
items = [["bob", 1], ["jeff", 2], ["wal-E", 2], ["bob", 1], ["bob", 10]],
result = Object.entries(items.reduce((r, [name, value]) => {
if (!(name in r) || r[name] > value) r[name] = value;
return r;
}, {}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }Using reduce is an elegant solution to acheive this
let items = [["bob",1],["jeff",2],["wal-E",2],["bob",1],["bob",10]];
const lowestItem = items.reduce((a, b) => a[1] < b[1] ? a : b);
console.log(lowestItem);Read more about Array.prototype.reduce here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce
You can store the name with the lowest number and the lowest number in two seperate variables, then loop through the array and check whether each array's second item is smaller than the lowest number.
If so, set the lowest number to the second item in the array and the lowest name to the first item in the array.
let items = [["bob",1],["jeff",2],["wal-E",2],["bob",1],["bob",10]]
let lowest;
let lowestName;
items.forEach(e => {
if(!lowest || e[1] < lowest){
lowest = e[1];
lowestName = e[0];
}
})
console.log(lowestName, lowest)