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¿El mejor lugar para limpiar Array antes de la iteración?

EDITAR: creo que iba por el camino equivocado al tratar de eliminar duplicados y necesitaba borrar la matriz en su lugar.

Aquí hay un código de ejemplo. Estoy tratando de encontrar el mejor lugar para borrar la matriz parent.subdirectories antes de cada iteración.

 const mainArray = [{Id:1,Name:"test",SubDirectoryCount:10,Files:[]}]; const directories = [{Id:56,Name:"Client 2",SubDirectoryCount:1,ParentId:1,Files:[]},{Id:53,Name:"Client 3",SubDirectoryCount:1,ParentId:1,Files:[]},{Id:50,Name:"Client 4",SubDirectoryCount:1,ParentId:1,Files:[]},{Id:48,Name:"Client 5",SubDirectoryCount:1,ParentId:53,Files:[]},{Id:47,Name:"Client 5",SubDirectoryCount:1,ParentId:53,Files:[]},{Id:49,Name:"Client 5",SubDirectoryCount:1,ParentId:53,Files:[]}]; // create flat list const tmp = mainArray.concat(directories); tmp.forEach(directory => { const parent = tmp.find(item => item.Id === directory.ParentId); if(parent) { parent.SubDirectories = parent.SubDirectories || []; parent.SubDirectories.push(directory) } }); console.log(mainArray)

Mi intento, pero elimina los elementos principales antes de reconstruir JSON.

 tmp.forEach((directory) => { const parent = tmp.find((item) => item.Id === directory.ParentFk); if (parent) { parent.SubDirectories = parent.SubDirectories || []; const found = parent.SubDirectories.some((el) => el.Id === directory.Id); if (!found) { parent.SubDirectories.push(directory); } else { parent.SubDirectories = []; } } }, []);
about 4 years ago · Juan Pablo Isaza
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simplemente eso?

 const directories = [ { Id: 56, Name: 'Client 2', SubDirectoryCount: 1, ParentId: 1, Files: [] } , { Id: 53, Name: 'Client 3', SubDirectoryCount: 1, ParentId: 1, Files: [] } , { Id: 50, Name: 'Client 4', SubDirectoryCount: 1, ParentId: 1, Files: [] } , { Id: 48, Name: 'Client 5', SubDirectoryCount: 1, ParentId: 53, Files: [] } , { Id: 47, Name: 'Client 5', SubDirectoryCount: 1, ParentId: 53, Files: [] } , { Id: 47, Name: 'Client 5', SubDirectoryCount: 1, ParentId: 53, Files: [] } ] for (let index= directories.length; --index;) { if (index > directories.findIndex(x=>x.Id===directories[index].Id)) directories.splice(index,1) } console.log( directories )
 .as-console-wrapper {max-height: 100%!important;top:0 }

about 4 years ago · Juan Pablo Isaza Report

0

Tu puedes hacer:

 const directories = [{Id: 56, Name: 'Client 2', SubDirectoryCount: 1, ParentId: 1, Files: []}, {Id: 53, Name: 'Client 3', SubDirectoryCount: 1, ParentId: 1, Files: []}, {Id: 50, Name: 'Client 4', SubDirectoryCount: 1, ParentId: 1, Files: []}, {Id: 48, Name: 'Client 5', SubDirectoryCount: 1, ParentId: 53, Files: []}, {Id: 47, Name: 'Client 5', SubDirectoryCount: 1, ParentId: 53, Files: []}, {Id: 47, Name: 'Client 5', SubDirectoryCount: 1, ParentId: 53, Files: []}] const result = Object.values(directories.reduce((a, c) => (a[c.Id] = a[c.Id] || c, a), {})) console.log(result)

about 4 years ago · Juan Pablo Isaza Report
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