I have 5 equations in Javascript, all are very similar, they take a number value, divide it by 60, then multiply it by another value. e.g.:
var a = 10;
var b = 1;
var c = 1;
var d = 15.5;
var e = 5
var a1 = 10;
var b1 = 1;
var c1 = 10;
var d1 = 15;
var e1 = 5
var calcOne = (a/60)*a1
var calcTwo = (b/60)*b1
var calcThree = (c/60)*c1
var calcFour = (d/60)*d1
var calcFive = (e/60)*e1
var finalValue = (calcOne + calcTwo + calcThree + calcFour + calcFive)
**finalValue = 6.154**
The values of the first two sets of variables can change, they can be any number at all, even 0's, what I want to do is compress the 5 calculations into 1, so I want to be able to get the 'finalValue' (6.154) value from one equation, and I would want it to work regardless of what the values are, e.g. I don't want to have to hardcode it.
For example, I have tried
(((a+b+c+d+e)/60) * (a1+b1+c1+d1+e1)) = 22.2425 //sum of first set, divided by 60, multiplied by sum of second set (value too big)
(((a+b+c+d+e)/300) * (a1+b1+c1+d1+e1)) = 4.4485 //sum of first set, divided by 300, multiplied by sum of second set (divided by 300 as there are 5 equations)
((((a+b+c+d+e)/5)/60) * (a1+b1+c1+d1+e1)) = 4.4485 //sum of first set divided by 5 , divided by 60, multiplied by sum of second set (divided by 5 before 60 as there are 5 equations)
(((a+b+c+d+e)/60) * ((a1+b1+c1+d1+e1/5))) = 4.4485 //sum of first set, divided by 60, multiplied by sum of second set (divided by 5 as there are 5 equations)
Any help would be appreciated, thank you.
You could take all values into arrays and reduce the arrays.
const
a = [10, 1, 1, 15.5, 5],
b = [10, 1, 10, 15, 5],
r = a.reduce((s, v, i) => s + v * b[i], 0) / 60;
console.log(r); // 6.154A slightly better approach is to use paired values.
const
values = [[10, 10], [1, 1], [1, 10], [15.5, 15], [5, 5]],
r = values.reduce((s, [a, b], i) => s + a * b, 0) / 60;
console.log(r); // 6.154you can just use the formula as
(a * a1 + b * b1 + c * c1 + d * d1 + e * e1)/60;
var a = 10;
var b = 1;
var c = 1;
var d = 15.5;
var e = 5
var a1 = 10;
var b1 = 1;
var c1 = 10;
var d1 = 15;
var e1 = 5
var calcOne = (a / 60) * a1
var calcTwo = (b / 60) * b1
var calcThree = (c / 60) * c1
var calcFour = (d / 60) * d1
var calcFive = (e / 60) * e1
var finalValue = (calcOne + calcTwo + calcThree + calcFour + calcFive);
var formula = (a * a1 + b * b1 + c * c1 + d * d1 + e * e1)/60;
console.log(finalValue,formula);You can easily achive the result using reduce
var a = 10;
var b = 1;
var c = 1;
var d = 15.5;
var e = 5;
var a1 = 10;
var b1 = 1;
var c1 = 10;
var d1 = 15;
var e1 = 5;
const first = [a, b, c, d, e];
const second = [a1, b1, c1, d1, e1];
const result = first.reduce((acc, curr, i) => acc + (curr / 60) * second[i], 0);
console.log(result);