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¿Cómo puedo hacer los tres console.log en una sola línea?

// codigo

 const arr1 = [17, 21, 34]; const printForecast = function (arr1) { for (var i = 0; i < arr1.length; i++) { console.log(`${arr1[i]} C on day ${arr1.indexOf(arr1[i]) + 1}`); } }; printForecast(arr1);

// Quiero una salida como esta--> 17 C el día 1 21 C el día 2 34 C el día 3

about 4 years ago · Juan Pablo Isaza
3 answers
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0

  1. Idealmente, su función debería devolver un valor.

  2. Use el map para iterar sobre la matriz, cree una nueva matriz de cadenas y join en una nueva cadena antes de devolverla.

 const arr1 = [17, 21, 34]; function getForecast(arr1) { return arr1.map((num, i) => { return `${num} C on day ${i + 1}`; }).join(', '); }; console.log(getForecast(arr1));

about 4 years ago · Juan Pablo Isaza Report

0

Construye la cuerda dentro del bucle. Asígnelo a una variable y luego imprímalo fuera del bucle for.

 const arr1 = [17, 21, 34]; const printForecast = function(arr1) { let string = ""; for (var i = 0; i < arr1.length; i++) { string += `${arr1[i]} C on day ${arr1.indexOf(arr1[i]) + 1}, `; } console.log(string); }; printForecast(arr1);

about 4 years ago · Juan Pablo Isaza Report

0

 const arr1 = [17, 21, 34]; arr1.forEach((item, index) => { console.log(`${item} C on day ${index + 1}`); });

about 4 years ago · Juan Pablo Isaza Report
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