Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

379
Views
RXJS Operador catcherror personalizado

Normalmente podría definir un operador personalizado y estructurar una tubería como esta:

 public custOperator = () => { return (source: Observable<any>) => { return source.pipe( map(val => { //do stuff with val }) ) } }; test(){ of().pipe( this.custOperator(), catchError(err => { //do stuff with err (more logic will go in here) throw err }) ).subscribe() }

Sin embargo, se está volviendo tedioso escribir la lógica de catcherror cada vez que necesito canalizar un observable.

¿Cómo haría para crear un operador similar, excepto que espera un error en lugar de un observable, de modo que imite catchError?

Actualizar

Pude crear un operador catcherror personalizado como tal:

 private customCatchOperator = () => { return catchError(err => { // handle error }) }
over 4 years ago · Santiago Trujillo
1 answers
Answer question

0

Puedes hacerlo de la siguiente manera:

 customCatchOperator() { return catchError(err => { // handle error }) }
over 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!