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Regex Capture Character and Replace with another

Trying to replace the special characters preceded by digits with dot.

const time = "17:34:12:p. m.";

const output = time.replace(/\d+(.)/g, '.');
// Expected Output "17.34.12.p. m."
console.log(output);

I had wrote the regex which will capture any character preceded by digit/s. The output is replacing the digit too with the replacement. Can someone please help me to figure out the issue?

about 4 years ago · Juan Pablo Isaza
2 answers
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0

You can use

const time = "17:34:12:p. m.";
const output = time.replace(/(\d)[\W_]/g, '$1.');
console.log(output);

The time.replace(/(\d)[\W_]/g, '$1.') code will match and capture a digit into Group 1 and match any non-word or underscore chars, and the $1. replacement will put the digit back and replace : with ..

If you want to "subtract" whitespace pattern from [\W_], use (?:[^\w\s]|_).

Consider checking more special character patterns in Check for special characters in string.

about 4 years ago · Juan Pablo Isaza Report

0

You should look for non word(\w) and non spaces (\s) characters and replace them with dot.

You should use some live simulator for regular expressions. For example regex101: https://regex101.com/r/xIStHH/1

const time = "17:34:12:p. m.";

const output = time.replace(/[^\w\s]/g, '.');
// Expected Output "17.34.12.p. m."
console.log(output);

about 4 years ago · Juan Pablo Isaza Report
Answer question
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