var a=[];
// Only change code below this line
function countdown(n){
if(n>=1){
countdown(n-1);
console.log(n);
a.push(n);
return a;
}
else{
return [];
}
}
console.log(countdown(5));Here I want to know after the recalling of the countdown function why the n is printed like 1,2,3,4,5? It should be 5,4,3,2,1?
In the initial call to countdown (where n=5) you recursively call countdown and then print n.
Switch the order of console.log(n); and countdown(n-1); and you will have expected behavior.
var a=[];
// Only change code below this line
function countdown(n){
if(n>=1){
console.log(n);
countdown(n-1);
a.unshift(n);
return a;
}
else{
return [];
}
}
console.log(countdown(5));