You can check for palindrome without a for loop.

function isPalindrome(string) {
  const toArray = string.replace(/ /g, '').toLowerCase().split('');
  const reverseArray = toArray.slice().reverse();
  const original = toArray.join('');
  const reversed = reverseArray.join('');
  if (original === reversed) {
    return true;
  } else {
    return false;
  };
}
isPalindrome('WORD HERE');

use

isPalindrome(name)

under the code

All you have to do is just to call the function with the user input.

Also remember to return from the function once the input is not found as a palindrome. Else function will log both Not Palindrome and Palindrome when the input is not palindrome

var name = prompt("Enter Name: ");
const isPalindrome = name => {
  const midPoint = name.length / 2;
  for (let i = 0; i < midPoint && i < name.length; i++) {
    if (name[i] != name[name.length - 1 - i]) {
      console.log(" Not Palindrome");
      return;
    }
  }
  console.log("Palindrome");
}
isPalindrome(name);