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Viewsiterate array of numbers to calculate all possible combinations with given algorithm - javscript
i need to iterate an array of x numbers in given order and calculate all possible combinations, for example:
I have this Array of 5 numbers [01,02,03,04,05], this is the condition to calculate the combinations:
expected output:
01 02 01 03 01 04 01 05 05 04 05 03 05 02 04 03 04 02 03 02
Example of array of 6 numbers [00,00,00,10,40,60], this is the condition to calculate the combinations:
expected output:
00 00 00 00 00 10 00 40 00 60 60 40 60 10 60 00 60 00 00 00 00 10 00 40 40 10 40 00 00 10
so the array can be from length 3 to x length.
this is what i have
function calculate(numbers){
let combinations = [];
if(numbers.length == 2){
combinations = [numbers[0] + ' '+ numbers[1]];
}else{
for(let i = 1; i < numbers.length; i++){
combinations.push(numbers[0] + ' '+ numbers[i]);
}
for(let i = numbers.length - 1; i >= 1; i--){
combinations.push(numbers[numbers.length - 1] + ' '+ numbers[i]);
}
}
return combinations
}
let numbers = [01,02,03,04,05];
console.log(calculate(numbers))thanks in advance
3 answers
Answer question0
I recreated the first example you gave in a more efficient manner, this also greatly simplifies the code:
Now for the code
const data = ["01", "02", "03", "04", "05"];
const possibilities = [];
for (let i = 0; i < data.length; i++) {
let j = i + 1;
while (j < data.length) {
possibilities.push(data[i] + " " + data[j]);
j++;
}
}
console.log(possibilities);0
nums.slice(0, nums.length-1).map(
(n, i) => nums.slice(i+1).map(
sn => `${n} ${sn}`
).join(' ')
).join(' ')
Hope it is what you want.
0
The way you connect the numbers made you think over complicated. If you connect them in this way, then the logic to get all possible combinations is simple. i.e. for each number, pair with every numbers after it. That's all.
const numbers = [1,2,3,4,5];
let combinations = [];
for(let i = 0 ; i < numbers.length; i++)
{
for(let j = i+1; j < numbers.length; j++)
{
combinations.push([numbers[i],numbers[j]]);
}
}
console.log(combinations);