Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

174
Views
javascript cálculo de edades y alturas de personas

Necesito tomar la suma de todas las edades y alturas de la persona.

Matriz de entrada:

 [ { "personId": 1, "ages": [ 1, 4, 5 ], "heights": [ 1, 1, 2 ] }, { "personId": 2, "ages": [ 4, 2, 2 ], "heights": [ 1, 4, 2 ] }, { "personId": 2, "ages": [ 2, 1, 1 ], "heights": [ 12 ] } ]

Salida deseada:

 [ { "type": "ages", "values": 22 }, { "type": "heights", "values": 23 } ]

Mi solución (que funciona perfectamente bien):

 var agesTotal = 0; var heightsTotal = 0; var resultArr = []; var sourceArr = [{personId: 1, ages: [1,4,5], heights: [1,1,2]}, {personId: 2, ages: [4,2,2], heights: [1,4,2]}, {personId: 2, ages: [2,1,1], heights: [12]}]; for(var i = 0; i < sourceArr.length; i++){ if(sourceArr[i].ages){ if(i == 0){ resultArr.push({ type: "ages", values: agesTotal }); } for(var n = 0; n < resultArr.length; n++){ if(resultArr[n].type == "ages"){ resultArr[n].values += agesTotal + sourceArr[i].ages.reduce((partialSum, a) => parseFloat(partialSum) + parseFloat(a), 0) } } } if(sourceArr[i].heights){ if(i == 0){ resultArr.push({ type: "heights", values: heightsTotal }); } for(var n = 0; n < resultArr.length; n++){ if(resultArr[n].type == "heights"){ resultArr[n].values += heightsTotal + sourceArr[i].heights.reduce((partialSum, a) => parseFloat(partialSum) + parseFloat(a), 0) } } } }

Este código mío anterior está produciendo la respuesta correcta, pero parece demasiado procesado y sin optimizar.

Lo que necesito es la mejor solución posible y optimizada para esta operación.

about 4 years ago · Santiago Trujillo
2 answers
Answer question

0

Sin un objetivo de rendimiento claramente definido, es difícil dar una respuesta que me parezca satisfactoria. Sin embargo, creo que esto es legible, conciso y sin desperdicio:

 function sumArrays (accumulator, obj) { for (const [key, value] of Object.entries(obj)) { if (!Array.isArray(value)) continue; accumulator[key] ??= 0; for (const n of value) accumulator[key] += n; } } function getSums (array) { const accumulator = {}; for (const obj of array) sumArrays(accumulator, obj); return Object.entries(accumulator).map(([type, values]) => ({type, values})); } // Or, instead, optimized only for the input keys: function getSumsOptimized (array, keysToSum) { const result = keysToSum.map(type => ({type, values: 0})); for (const obj of array) { for (const [index, key] of keysToSum.entries()) { for (const n of obj[key]) result[index].values += n; } } return result; } const input = [ { personId: 1, ages: [1, 4, 5], heights: [1, 1, 2]}, { personId: 2, ages: [4, 2, 2], heights: [1, 4, 2]}, { personId: 2, ages: [2, 1, 1], heights: [12 ]}, ]; console.log(getSums(input)); console.log(getSumsOptimized(input, ['ages', 'heights']));

about 4 years ago · Santiago Trujillo Report

0

 const array = [ { "personId": 1, "ages": [ 1, 4, 5 ], "heights": [ 1, 1, 2 ] }, { "personId": 2, "ages": [ 4, 2, 2 ], "heights": [ 1, 4, 2 ] }, { "personId": 2, "ages": [ 2, 1, 1 ], "heights": [ 12 ] } ] let heightsSum = 0; let agesSum = 0; array.forEach(element => { element.ages.forEach(age => { agesSum += age; }) element.heights.forEach(height => { heightsSum += height; }) }) const arr = [ { type: 'ages', values: agesSum }, { type: 'heights', values: heightsSum } ] console.log(arr)

about 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!