Here is my dictionary:
const dict = {
"key_1" : "z",
"key_2" : "a",
"key_3" : "b",
"key_4" : "y"
};
I want to sort it alphabetically by value so it looks like this:
const sorted_dict = {
"key_2" : "a",
"key_3" : "b",
"key_4" : "y",
"key_1" : "z"
};
This is what I think should work:
var items = Object.keys(dict).map(function(key) {
return [key, dict[key]];
});
items.sort((a, b) => a[1] - b[1]);
console.log(items)
But it's not sorting at all:
[
[
"key_1",
"z"
],
[
"key_2",
"a"
],
[
"key_3",
"b"
],
[
"key_4",
"y"
]
]
Why is the sorting not working?
Hope this code will help you
const dict = {
key_1: "z",
key_2: "a",
key_3: "b",
key_4: "y",
};
const sortable = Object.fromEntries(
Object.entries(dict).sort(([, a], [, b]) => a.localeCompare(b))
);
console.log(sortable);There is no such thing as a sorted dictionary in JavaScript. There is no guarantee that insertion order nor alphabetical order will be preserved, even if you sometimes get the illusion that it is, you should never rely on it. If you need order you must use an array, a set or a Map
The following code will sort the dictionary by the charcode, meaning the order of the alphabet:
const dict = {
"key_1" : "z",
"key_2" : "a",
"key_3" : "b",
"key_4" : "y"
};
const sorted = Object.entries(dict)
.sort(([, v1], [, v2]) => v1.toUpperCase().charCodeAt(0) - v2.toUpperCase().charCodeAt(0))
.reduce((obj, [k, v]) => ({
...obj,
[k]: v
}), {})
console.log(sorted)
//{key_2: 'a', key_3: 'b', key_4: 'y', key_1: 'z'}
However, this will only work when the value is one character. Do you which for a function that also sorts bigger values?