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0

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How to move duplicate to first index in an array of Objects?

I have below variable with array of Objects

let Obj1 =

    [
    {Id: 123, name: 'A'},
    {Id: 124, name: 'B'},
    {Id: 125, name: 'C'},
    {Id: 126, name: 'D'},
    {Id: 127, name: 'E'}
    ]

let Obj2 = {Id:126, name: 'D'}

How do I move the Obj2 in Obj1 to the 0th index dynamically in Javascript or TypeScript? Obj2 is from backend and Obj1 is the data already present in frontend The End result should be as below

[
{Id: 126, name: 'D'},
{Id: 123, name: 'A'},
{Id: 124, name: 'B'},
{Id: 125, name: 'C'},
{Id: 127, name: 'E'}
]
about 4 years ago · Santiago Gelvez
3 answers
Answer question

0

let Obj1 =
    [
    {id: 123, name: 'A'},
    {id: 124, name: 'B'},
    {id: 125, name: 'C'},
    {id: 126, name: 'D'},
    {id: 127, name: 'E'}
    ];

let Obj2 = {id:126, name: 'D'};

let new_array = Obj1.reduce((curr, acc)=>(acc.id === Obj2.id ? curr.unshift(acc) : curr.push(acc), curr), []);

console.log(new_array);
about 4 years ago · Santiago Gelvez Report

0

Please try this

let Obj1 = [
   {
      "Id":123,
      "name":"A"
   },
   {
      "Id":124,
      "name":"B"
   },
   {
      "Id":125,
      "name":"C"
   },
   {
      "Id":126,
      "name":"D"
   },
   {
      "Id":127,
      "name":"E"
   }
]

let Obj2 = {
    "Id":126, 
    "name":"D"
}

/* 

if Obj2 isn't in the array called Obj1...
put Obj2 at the front of the Obj1 array

*/

if (Obj1.indexOf(Obj2) == -1) {
  Obj1.unshift(Obj2);
}
about 4 years ago · Santiago Gelvez Report

0

let Obj1 =

    [
        {Id: 123, name: 'A'},
        {Id: 124, name: 'B'},
        {Id: 125, name: 'C'},
        {Id: 126, name: 'D'},
        {Id: 127, name: 'E'}
    ]

let Obj2 = {Id:126, name: 'D'}

for (let i = 0; i < Obj1.length; i++) {
    if (Obj1[i].Id === Obj2.Id && Obj1[i].name === Obj2.name) {
        Obj1.splice(i, 1)
        Obj1.unshift(Obj2)
        break
    }
}

console.log(Obj1)

about 4 years ago · Santiago Gelvez Report
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