Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

153
Views
Issue with random sampling

I'm trying to pick a random element from an array without picking the same element twice.

After a few iterations it is undefined.

It works with return(pick_random_letter()). But WHY?

Why does pick_random_letter() not go back and return later?

let letters = [
{ name: 'A' },
{ name: 'B' },
{ name: 'C' },
{ name: 'D' },
]

let used_letters = [];

function pick_random_letter(){
  let random = Math.floor(Math.random() * letters.length);
  let next_letter = letters[random].name;
  if (used_letters.includes(next_letter)){
    if (used_letters.length == letters.length) used_letters = [];
    pick_random_letter(); // return(pick_random_letter()) works
  }else{
    used_letters.push(next_letter);
    return next_letter;
  }
}

for (let i = 0; i < 4; i++){
    let random_letter = pick_random_letter();
    console.log(random_letter);
    console.log(used_letters);
}

Working example:

let letters = [
{ name: 'A' },
{ name: 'B' },
{ name: 'C' },
{ name: 'D' },
]

let used_letters = [];

function pick_random_letter(){
  let random = Math.floor(Math.random() * letters.length);
  let next_letter = letters[random].name;
  if (used_letters.includes(next_letter)){
    if (used_letters.length == letters.length) used_letters = [];
    return(pick_random_letter());
  }else{
    used_letters.push(next_letter);
    return next_letter;
  }
}

for (let i = 0; i < 4; i++){
    let random_letter = pick_random_letter();
    console.log(random_letter);
    console.log(used_letters);
}

Thank you

about 4 years ago · Santiago Gelvez
1 answers
Answer question

0

I think you would be better off using a shuffling approach. Create a shuffled list of your letters and pick from these. This avoids any need to check if we've returned a letter previously.

We'd start by creating a shuffledLetters array, then each time we call pick_random_letter() we return the next value.

The shuffle() function here is a basic Fisher–Yates / Knuth shuffle.

function shuffle(arr) {
  for (let i = arr.length - 1; i > 0; i--) {
    const j = Math.floor(Math.random() * (i + 1));
    [arr[i], arr[j]] = [arr[j], arr[i]];
  }
  return arr;
}

let letters = [
  { name: 'A' },
  { name: 'B' },
  { name: 'C' },
  { name: 'D' },
]

// Create a shuffled copy of the letters array
let shuffledLetters = shuffle([...letters]);

function pick_random_letter() {
  return shuffledLetters.pop();
}

for (let i = 0; i < letters.length; i++) {
  let random_letter = pick_random_letter();
  console.log(random_letter);
}
.as-console-wrapper { max-height: 100% !important; }

about 4 years ago · Santiago Gelvez Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!