I only want to return the socket id, but forEach returns an undefined value, and find returns the entire object.
I only want the output to be 12345.
const users= [
{ host: true, socketId: "12345" },
{ host: false, socketId: "987654" },
{ host: false, socketId: "5678345" },
];
let socketId = users.forEach((user) => {
if (user.host === true) {
return user.socketId;
}
});//this return undefined
let socketId = users.find((user) => {
if (user.host === true) {
return user.socketId;
}
});//this return the whole object {host:true,socketId:"12345"}
const getHostSocketId = () => {
for (var i = 0; i < users.length; i++) {
if (users[i].host === true) {
return users[i].socketId;
}
}
};
let socketId = getHostSocketId(); //This works, but I'd rather use a method like the ones mentioned above.
console.log(socketId); //i want this to be 12345
let socketId = users.find(u => u.host)?.socketId
let answer = (inputArray) => {
const outputArray = []
inputArray.forEach((element) => {
if (element.host === true) {
outputArray.push(element.socketId)
}
})
return JSON.stringify(outputArray, null, ' ')
}