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Is it possible to create strict 'A or B' types in TypeScript?

I've run into an issue with typing React components that I've never run into before. I've simplified the issue below.

interface Circle {
  kind?: "circle";
  radius: number;
}
 
interface Square {
  kind: "square";
  sideLength: number;
}
 
type Shape = Circle | Square;

const shape: Shape = {
  sideLength: 7,
  radius: 7,
};

Link to TypeScript Playground containing the above

In the example above, I'd expect the shape variable declaration to throw an error in TypeScript as neither a Circle nor a Square have both a sideLength and a radius. The defined object is neither a Circle nor a Square, so in my eyes it shouldn't be a valid shape.

Is it possible to define the types in such a way that the following items will be valid or errors (as labelled).

// Valid
const shape: Shape = {
  kind: 'circle',
  radius: 7,
};

// Valid
const shape: Shape = {
  radius: 7,
};

// Valid
const shape: Shape = {
  kind: 'square',
  sideLength: 7,
};

// Error
const shape: Shape = {
  sideLength: 7,
  radius: 7,
};

// Error
const shape: Shape = {
  sideLength: 7,
};

// Error
const shape: Shape = {
  kind: 'square',
  radius: 7,
};

// Error
const shape: Shape = {
  kind: 'circle',
  sideLength: 7,
};

EDIT:

For further clarification, in my use-case kind is optional on a Circle. For those familiar with React the actual problem I'm trying to solve is around the as property exposed by styled-components. I want a component to accept an optional as prop which will allow the user to change the component (by-default a button) to a link (a). If the user specifies as="a" then I want TypeScript to compalin if the user then tries to use button-specific props on what is now a link (disabled, for example). The as prop is optional as I don't want all implementors to be required to pass it. In my simplified example above as is analagous to kind, hence why kind is optional.

about 4 years ago · Juan Pablo Isaza
1 answers
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0

Note that you have defined kind property as an optional property, so if you create a shape object with only radius property is still valid circle:

Look at this object

const shape: Shape = {
  sideLength: 7,
  radius: 7,
};

This is valid circle with one extra property.

So to raise an error in some case you've said, you should make kind property as a required property:

interface Circle {
  kind: "circle";
  radius: number;
}
 
interface Square {
  kind: "square";
  sideLength: number;
}
 
type Shape = Circle | Square;

const shape2: Shape = {
  radius: 7,//Error
};

PlaygroundLink

about 4 years ago · Juan Pablo Isaza Report
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