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¿Cómo obtener el resultado solo en lugar del resultado adjunto al elemento?

Quiero devolver los datos que coincidan solo con el valor de entrada.

Pero en este código, el resultado se agregará después de los datos.

Estoy atascado en list.append(div);

 const list = document.querySelector(".list"); const filterInput = document.querySelector("#filter-input"); const data = [{name: "abc"}, {name: "adb"}, {name: "cab"}]; renderData(data) function renderData(data) { data.forEach(item => { const div = document.createElement("div"); div.setAttribute("class", "item"); div.innerHTML = `<div class="name">${item.name}</div>`; list.append(div); }) } filterInput.addEventListener("input", e => { const keyword = e.target.value; let filteredData = data.filter(item => { return item.name.includes(keyword); }); renderData(filteredData); })
 <input type="text" id="filter-input"> <div class="list"></div>

about 4 years ago · Juan Pablo Isaza
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Borre el innerHTML de la lista al renderizar para eliminar los elementos agregados previamente:

 const list = document.querySelector(".list"); const filterInput = document.querySelector("#filter-input"); const data = [{name: "abc"}, {name: "adb"}, {name: "cab"}]; renderData(data) function renderData(data) { list.innerHTML = ""; //<-- clear innerHTML, remove appended elements data.forEach(item => { const div = document.createElement("div"); div.setAttribute("class", "item"); div.innerHTML = `<div class="name">${item.name}</div>`; list.append(div); }) } filterInput.addEventListener("input", e => { const keyword = e.target.value; let filteredData = data.filter(item => { return item.name.includes(keyword); }); renderData(filteredData); })
 <input type="text" id="filter-input"> <div class="list"></div>

about 4 years ago · Juan Pablo Isaza Report
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