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django actualiza el elemento div después de la búsqueda

Estoy tratando de crear una aplicación de tareas cuando busco una palabra, muestra la tabla sin actualizar toda la página.

aquí está mi index.html

 <body> <h2>My Personal TodoApp Project</h2> <br> <form action="/searchlist/" method="get">{%csrf_token%} <input type="text" name="content" placeholder="Search a todolist" class="form-control"> <input class="button button2" type="submit" name="submit" value="Search"/> </form> # where i want my table diplay after searching a particular word <div id="list"></div> <script type="text/javascript"> $.ajax({ var url = '/templates/searchlistdiv/', $('#list).show(); var div = $('#list'); div.load(url); )} </script> </body>

y mis vistas.py

 def searchtodolist(request): if request.method == 'GET': query = request.GET.get('content', None) if query: results = Todoitem.objects.filter(content__contains=query) return render(request, 'searchlistdiv.html', {"results": results}) return render(request, 'searchlistdiv.html')

y por último mi searchlistdiv.html

 <table> <tr> <th colspan="2">List of Todos</th> </tr> {% for result in results %} <tr> <td>{{result.content}}</td> <td><form action="/deleteTodo/{{todo_items.id}}/" style="display: inline; " method="post"> {%csrf_token%} <input class="button button1" type="submit" value="Delete"/> </form></td> </tr> {% endfor %} </tr> </table>

Estoy 100% seguro de que a mi js le falta algo, simplemente no sé lo que realmente no planeo aprender js todavía tratando de concentrarme en la parte de desarrollo de back-end (tal vez en el futuro aprenderé front-end)

about 4 years ago · Juan Pablo Isaza
1 answers
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0

Puedes hacer eso con esto:

 <form id="form_id" action="" method="get">{%csrf_token%} <input type="text" name="content" placeholder="Search a todolist" class="form-control"> <input class="button button2" type="submit" name="submit" value="Search"/> </form> <script> $("#form_id").submit(function (e) { e.preventDefault(); //this is what i use do prevent default action. [send request without refreshing the whole page] var serializedData = $(this).serialize(); $.ajax({ type: 'GET', url: "{% url '/searchlist/' %}", //url to your view. data: serializedData, success: function (response) { $("#list").html(response.searchlistdiv); // Where $("#list") is the container of "searchlistdiv" }, error: function (response) { alert('Error'); } }) }) </script>

en tus vistas.py:

 from django.template.loader import render_to_string from django.http import JsonResponse def searchtodolist(request): if request.method == 'GET': query = request.GET.get('content', None) if query: results = Todoitem.objects.filter(content__contains=query) d_partner_html = render_to_string("searchlistdiv.html", {"results": results}, request) return JsonResponse({'searchlistdiv': d_partner_html}) return render(request, 'searchlistdiv.html')
about 4 years ago · Juan Pablo Isaza Report
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