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Filtering a table in javascript

I'm trying to filter a table using a JavaScript function, but I'm not sure what the issue is...When clicking the filter link, nothing happens, but it should be filtering the second column ("Platform" column) and only displaying rows with "TEST" in it.

I'm trying to debug it here:

https://jsfiddle.net/7vh5wmsx/

function filterTable(input) {
        var filter = input.value.toUpperCase();
        var table = document.getElementById("myTable");
        var tr = table.getElementsByTagName("tr");
        var tds = tr.getElementsByTagName('td');

        for (var i = 0; i < tr.length; i++) {
            if (tds[1].textContent.toUpperCase().indexOf(filter) > -1) {
                tr[i].style.display = "";
            } else {
                tr[i].style.display = "none";
            }
        }
    }
about 4 years ago · Juan Pablo Isaza
1 answers
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0

Use this code

function myFunction() {
  // Declare variables
  var input, filter, table, tr, td, i, txtValue;
  input = document.getElementById("myInput");
  filter = input.value.toUpperCase();
  table = document.getElementById("myTable");
  tr = table.getElementsByTagName("tr");

  // Loop through all table rows, and hide those who don't match the search query
  for (i = 0; i < tr.length; i++) {
    td = tr[i].getElementsByTagName("td")[0];
    if (td) {
      txtValue = td.textContent || td.innerText;
      if (txtValue.toUpperCase().indexOf(filter) > -1) {
        tr[i].style.display = "";
      } else {
        tr[i].style.display = "none";
      }
    }
  }
}

about 4 years ago · Juan Pablo Isaza Report
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