i have an array of strings with duplicated letters , Now i want to count the number of duplicated letters from each string and need to create a separate object for each string. The given array :
let ArrOfStrs = ["aaabbbccc", "dddeeefff", "ggghhhiii", "jkl"]
what i have tried :
var obj={}
var repeats=[];
for(let i=0; i< ArrOfStrs.length; i++) {
for(let x = 0; x < ArrOfStrs[i].length; x++) {
var l = ArrOfStrs[i].charAt(x);
obj[l] = (!obj.hasOwnProperty(l) ? 1 : obj[l] + 1);
}
}
repeats.push(obj);
console.log(repeats);
Actual output :
{ a: 3, b: 3, c: 3, d: 3, e: 3, f: 3, g: 3, h: 3, i: 3, j: 1, k: 1, l: 1 }
Expected output :
[{a:3,b:3,c:3}, {d:3,e:3,f:3},{g:3,h:3,i:3},{j:1,k:1,l:1}]
Could some one help for better approach to achieve this. Thanks in advance.
... to convert String to Arrayconst arrOfStrs = ["aaabbbccc", "dddeeefff", "ggghhhiii", "jkl"];
const counted = arrOfStrs.map(str => [...str].reduce((o, v) => {
o[v] ??= 0 // set default count to 0 (if not exists)
o[v]++ // increment count
return o;
}, {}));
console.log(counted);Additional read:
Variant:
const arrOfStrs = ["aaabbbccc", "dddeeefff", "ggghhhiii", "jkl"];
const counted = arrOfStrs.map(s => [...s].reduce((o, v) => (o[v] ??= 0, o[v]++, o), {}));
console.log(counted);2 mistakes :
obj and making changes to it. Infact obj will be different for every string.obj into your result array for every iteration. You are doing it in the end, hence you have only one item in your array.Making minimal changes, your code can be fixed:
let ArrOfStrs = ["aaabbbccc", "dddeeefff", "ggghhhiii", "jkl"]
var repeats=[];
for(let i=0; i< ArrOfStrs.length; i++) {
var obj={}
for(let x = 0; x < ArrOfStrs[i].length; x++) {
var l = ArrOfStrs[i].charAt(x);
obj[l] = (!obj.hasOwnProperty(l) ? 1 : obj[l] + 1);
}
repeats.push(obj);
}
console.log(repeats);