I got a code block like this
const numbers = [1, 2, 3, 4, 5, 6];
const newNumbers = numbers.reduce((acc, num) => {
acc.push(num > 3 ? num : null);
return acc;
}, []);
console.log('new Numbers', newNumbers);
//returns new Numbers,[null, null, null, 4, 5, 6]
But I don't want null values to be pushed in array. I want to perform the action like this but without if:
const newNumbers = numbers.reduce((acc, num) => {
if (num > 3) {
acc.push(num);
}
return acc;
}, []);
console.log(newNumbers);
//returns new Numbers,[4, 5, 6]
How Can I Use Ternary Conditional Operator Without Else?
No. The conditional operator always has to "return" a value. Imagine it was possible to leave out the alternative (e.g. arr.push(num > 3 ? num)), what value would be pushed to the array?
In this specific case there is a better tool for the job: Array#filter:
const newNumbers = numbers.filter(num => num > 3)
Use && instead of ?,
const numbers = [1, 2, 3, 4, 5, 6];
const newNumbers = numbers.reduce((acc, num) => {
num > 3 && acc.push(num)
return acc;
}, []);
console.log(newNumbers);
//returns new Numbers,[4, 5, 6]
You can always do:
num > 3 ? acc.push(num) : {}