Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

224
Views
Julia ccall: Problem with shared library interfacing hardware devices

I am using Julia to control a camera which comes with a shared library on Linux-Mint. The shared library provides APIs written in C++. There are also header files containing definitions of types and constants concerning the device. I wrote Julia scripts to wrap C structs, definitions, enums and types with Julia. Here is the critical point. I use ccall function to call a function in the shared library . This function is supposed to return an opaque handle of the device. I use this format variant ccall( (:function, "library"), ...). An error code saying no camera is found was thrown back. Then, I tried preloading the shared library using Libdl.dlopen and use ccall(:function,..., ...) to call the function, but still got the same result. The same operation works perfectly fine in C.

I am wondering what could block connection to hardware devices when using ccall. I do not know the details of ccall implementation in Julia. If anybody can give me some clues, that would be great help.

Have a nice day,

Sitthichat

over 4 years ago · Santiago Trujillo
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!