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Agregue un parámetro opcional a la función de clase base, ignore en la subclase

Si tengo una jerarquía de clases y la uso de la siguiente manera, incluida una subclase de terceros que no puedo cambiar

 class Base: def doit(self): pass class Sub(Base): def doit(self): print('hi') class SubInThirdPartyLibrary(Base): def doit(self): print('hi from library') def doit(x: Base): x.doit() doit(Sub()) doit(SubInThirdPartyLibrary())

¿Hay alguna forma en que pueda agregar un parámetro opcional a la clase base, usarlo en la subclase, sin romper la clase de terceros?

 class Base: def doit(self, msg: str = 'hi'): pass class Sub(Base): def doit(self, msg: str = 'hi'): print(msg) class SubInThirdPartyLibrary(Base): def doit(self): # This isn't mine, I can't add the parameter here but want it to keep working. print('hi from library') def doit(x: Base): x.doit(hi='hello') doit(Sub()) doit(SubInThirdPartyLibrary()) # TypeError: doit() takes 1 positional argument but 2 were given
over 4 years ago · Santiago Trujillo
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Puede usar inspect.signature . firma:

 import inspect def doit(x: Base): sig = inspect.signature(x.doit) if 'msg' in sig.parameters: x.doit(msg='hello') else: x.doit()

Recomendaría no hacer esto y, en su lugar, probar otra solución.

over 4 years ago · Santiago Trujillo Report
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