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Python asyncio: how are tasks scheduled?

I'm new to Python asyncio and I'm doing some experiments. I have the following code:

async def say_after(n, s):
    await asyncio.sleep(n)
    print(s)

async def main():
    task1 = asyncio.create_task(say_after(2, 'a'))
    task2 = asyncio.create_task(say_after(1, 'b'))
    await task1
    print('x', flush=True)
    await task2
    print('y', flush=True)

asyncio.run(main())

And the output:

b
a
x
y

I don't understand the order here. Can someone help explain? Especially why x comes after b and a?

over 4 years ago · Santiago Trujillo
1 answers
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0

Especially why x comes after b and a?

b is printed in task2 about 1 second after the start of main, and a is printed in task1 about 2 seconds after the start of main. The await task1 waits for task1, and so waits about 2 seconds. So by the time await task1 completes, both b and a would have been printed.

(The "about"s in the above are deliberate... there would be variations, but in most situations, they would be small)

over 4 years ago · Santiago Trujillo Report
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