I have a file named example.txt and inside the file I have numbers from 1 -50 but I only want to view number within a particular range like 1-25
I tried this command:
less example.txt | grep [1-25]
but this didn't help, please help
IMHO the best way would be to use mathematical condition check rather than regex, please try following awk program.
awk '$0>=0 && $0<=25' Input_file
Above will work if your lines are containing only digits eg:
1
2
3
.....
In case your Input_file's lines can contain multiple digits that you want to print then better to loop through them and apply conditions to them and print them then.
awk '{for(i=1;i<=NF;i++){if($i>=0 && $i<=25){print $i}}}' Input_file
[1-25] means match group of characters consisting of characters between 1 and 2 and character 5. It's the same as [125] - match any of 1 2 or 5.
You can:
grep '[1-9]\|1[0-9]\|2[0-5]'
Match digits 1 to 9, or match 1 followed by digit 0 to 8, or match 2 followed by digit 0 to 5. Maybe add -w, see man grep.
I recommend regex crosswords for learning regex.