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Cómo actualizar el elemento div hijo en el éxito de ajax en php

Quiero actualizar el div secundario, pero todos los div se actualizan con el éxito de ajax.

mi html

 <div class="add_wishlist"> <input type="hidden" name="prd_wishlist" class="prd_wishlist" value="1"> <div class="wishlist_icon"> <p><i class="far fa-heart"></i></p> </div> </div> <div class="add_wishlist"> <input type="hidden" name="prd_wishlist" class="prd_wishlist" value="2"> <div class="wishlist_icon"> <p><i class="far fa-heart"></i></p> </div> </div>

jquery

 $('.add_wishlist').click(function(){ var prd_wish = $(this).find("[name='prd_wishlist']").val() $.ajax({ type: 'post', url: weburl+'pages/login-script.php', data: { prd_wish:prd_wish, wishlist_submit:'submit', }, success: function (response) { $('.add_wishlist').children('.wishlist_icon').html(response) } }); })

También traté de actualizar el código con $('.add_wishlist').children('.wishlist_icon').html(response) pero no funciona.

over 4 years ago · Santiago Trujillo
1 answers
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0

Almacene una referencia al elemento .add_wishlist en el que se hizo clic en el controlador de clics, luego utilícelo dentro del controlador de success :

 $('.add_wishlist').click(function() { let $addWishlist = $(this); let prd_wish = $addWishlist.find("[name='prd_wishlist']").val() $.ajax({ type: 'post', url: weburl + 'pages/login-script.php', data: { prd_wish: prd_wish, wishlist_submit: 'submit', }, success: function(response) { $addWishlist.children('.wishlist_icon').html(response); } }); })
over 4 years ago · Santiago Trujillo Report
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