The goal is to pass a constant array, (representing the member variables of the corresponding structure parameter) like {{"network", "lan"}, {"dhcp", "true"}} as parameter when calling a function like:
ubus_call("router", "client", {{"network", "lan"}, {"dhcp", "true"}}, 2);
I tried the following code but it returns errors in the compilation:
struct ubus_args {
char *key;
char *val;
};
int ubus_call(char *obj, char *method, struct ubus_args u_args[], int size_args) {
printf("%s\n", obj);
printf("%s\n", method);
printf("%s %s\n", u_args->key, u_args->val);
return 0;
}
int main ()
{
ubus_call("router", "client", {{"network", "lan"}, {"dhcp", "true"}}, 2);
return 0;
}
How I can do that in the proper way?
Here is the complete program, you can try it out.
#include <stdio.h>
struct ubus_args {
char *key;
char *val;
};
int ubus_call(char *obj, char *method, struct ubus_args u_args[], int size_args) {
printf("%s\n", obj);
printf("%s\n", method);
printf("%s %s\n", u_args[0].key, u_args[0].val);
printf("%s %s\n", u_args[1].key, u_args[1].val);
return 0;
}
int main ()
{
ubus_call("router", "client", (struct ubus_args[2]){{"network", "lan"}, {"dhcp", "true"}}, 2);
return 0;
}
The program is tested on GNU GCC v4.8.3 online compiler.
If you're equipped with a C99 and above supported compiler, you can use compound literals to get your job done.
You can rewrite the function call like
ubus_call("router", "client", (struct ubus_args[]){{"network", "lan"}, {"dhcp", "true"}}, 2);
and it will work.
BTW, the recommended signature of main() is int main(void).