i am currently confused as to how i can pass an array of strings to a function. I have created a one-dimensional array. The method that i have done works but it seems redundant and i think there is a better way of doing this yet i am unsure how. I am trying to find a way where i can pass all 4 elements to the function at one time.
Here is the sample of my code.
#include <stdio.h>
#include <string.h>
#include <ctype.h>
void sort(char *,char *,char *, char *);//Function prototype
int main()
{
char *string_database[4]={'\0'};
string_database[0]="Florida";
string_database[1]="Oregon";
string_database[2]="California";
string_database[3]="Georgia";
sort(string_database[0],string_database[1],string_database[2],string_database[3]);
return 0;
}
void sort(char *string1, char *string2, char *string3, char *string4)
{
printf("The string is= %s\n",string1);
printf("The string is= %s\n",string2);
printf("The string is= %s\n",string3);
printf("The string is= %s\n\n\n",string4);
}
Thank you in advance, i appreciate any replies to my problem.
You can do it like this:
void sort(char **, int);
int main()
{
char *string_database[5]={'\0'};
string_database[0]="Florida";
string_database[1]="Oregon";
string_database[2]="California";
string_database[3]="Georgia";
sort(string_database, 4);
return 0;
}
void sort(char **str, int n)
{
int i = 0;
for (i = 0; i < n; i++)
printf("The string is= %s\n",str[i]);
}
#include <stdio.h>
#include <string.h>
#include <ctype.h>
void sort(char *strings[], int n);//Function prototype
int main()
{
char *string_database[4]={'\0'};
string_database[0]="Florida";
string_database[1]="Oregon";
string_database[2]="California";
string_database[3]="Georgia";
sort(string_database, 4);
return 0;
}
void sort(char *strings[], int n)
{
int i;
for (i=0; i<n; i++) {
printf("String %d: %s\n", i, strings[i]);
}
}
You usually pass the length of the array along with the array itself. The char *strings[] is really just sintactic sugar though, so if you want to keep the function prototype without parameter names you can use char **strings as well, so that the code could be like this:
#include <stdio.h>
#include <string.h>
#include <ctype.h>
void sort(char **, int);//Function prototype
int main()
{
char *string_database[4]={'\0'};
string_database[0]="Florida";
string_database[1]="Oregon";
string_database[2]="California";
string_database[3]="Georgia";
sort(string_database, 4);
return 0;
}
void sort(char **strings, int n)
{
int i;
for (i=0; i<n; i++) {
printf("String %d: %s\n", i, strings[i]);
}
}
Also, as Jite below points out, using a syntax such as char *strings[] might mislead you or another reader of the code into thinking they're dealing with a static matrix, while this is not true; you should therefore opt for the more straightforward char **strings syntax.
after reading all the answer given for your question. I would like to tell you one more thing. you can also print your strings, character by character.
void sort(char **, int);
int main()
{
char *string_database[5]={'\0'};
string_database[0]="Florida";
string_database[1]="Oregon";
string_database[2]="California";
string_database[3]="Georgia";
sort(string_database, 4);
return 0;
}
void sort(char **str, int n)
{
int i = 0;
for (i = 0; i < n; i++)
{
for (int j=0;str[i][j]!='\0';j++)
{
printf("%c",str[i][j]);
}
printf("\n");
}
}
as str is a double-pointer, we can use two subscripts without any problem to get to characters.