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ViewsAWS Fargate - How to get the public ip address of task by using python boto3
I am creating new fargate task by using the following python script.
import boto3
import json
def handler():
client = boto3.client('ecs')
response = client.run_task(
cluster='fargate-learning', # name of the cluster
launchType = 'FARGATE',
taskDefinition='fargate-learning:1', # replace with your task definition name and revision
count = 1,
platformVersion='LATEST',
networkConfiguration={
'awsvpcConfiguration': {
'subnets': [
'subnet-0a024d8ac87668b64', # replace with your public subnet or a private with NAT
],
'assignPublicIp': 'ENABLED'
}
})
print(response)
return str(response)
if __name__ == '__main__':
handler()
And here is the response I am getting from boto3.
https://jsonblob.com/5faf3ae6-bc31-11ea-8cae-53bd90c38587
I can not see the public ip address in response although the script is assigning the public ip address and I can see it on website.
So, how can I get this public ip address by using boto3?
Thanks
2 answers
Answer question0
This can be done in two steps:
Use describe_tasks to get ENI id associated with your fargate
awsvpcinterface. The value of eni, e.g.eni-0c866df3faf8408d0, will be given inattachmentsanddetailsfrom the result of the call.Once you have the eni, then you can use EC2.NetworkInterface. For example:
eni_id = 'eni-0c866df3faf8408d0' # from step 1
eni = boto3.resource('ec2').NetworkInterface(eni_id)
print(eni.association_attribute['PublicIp'])
0
Tried implementing @Marcin 's answers as a function. Hope this can be helpful
def get_service_ips(cluster, tasks):
tasks_detail = ecs.describe_tasks(
cluster=cluster,
tasks=tasks
)
# first get the ENIs
enis = []
for task in tasks_detail.get("tasks", []):
for attachment in task.get("attachments", []):
for detail in attachment.get("details", []):
if detail.get("name") == "networkInterfaceId":
enis.append(detail.get("value"))
# now the ips
ips = []
for eni in enis:
eni_resource = boto3.resource("ec2").NetworkInterface(eni)
ips.append(eni_resource.association_attribute.get("PublicIp"))
return ips
as a gist here.