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¿Cómo encontrar el tipo de triángulo (se da la longitud de los tres lados) usando el caso anidado en mysql?

Tabla de muestra

¿Qué es wrobg en esta consulta de MySQL? Está mostrando un error de sintaxis.

 SELECT CASE WHEN A = B CASE WHEN A = C THEN 'Equilateral' WHEN C < A + B THEN 'Isosceles' ELSE 'Not A Triangle' END WHEN B = C CASE WHEN A < B + C THEN 'Isosceles' ELSE 'Not A Triangle' END WHEN A + B > C AND A + C > B AND B + C > A THEN 'Scalene' ELSE 'Not A Triangle' END FROM TRIANGLES;
over 4 years ago · Santiago Trujillo
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0

Tienes que agregar también un luego para ese propósito

 SELECT CASE WHEN A = B THEN CASE WHEN A = C THEN 'Equilateral' WHEN C < A + B THEN 'Isosceles' ELSE 'Not A Triangle' END WHEN B = C THEN CASE WHEN A < B + C THEN 'Isosceles' ELSE 'Not A Triangle' END WHEN A + B > C AND A + C > B AND B + C > A THEN 'Scalene' ELSE 'Not A Triangle' END FROM TRIANGLES;
over 4 years ago · Santiago Trujillo Report

0

No hay necesidad de anidar expresiones de case y minúsculas:

 SELECT (CASE WHEN A = B AND A = C THEN 'Equilateral' WHEN A = B AND C < A + B THEN 'Isosceles' WHEN A = B THEN 'Not A Triangle' WHEN B = C AND A < B + C THEN 'Isosceles' WHEN B = C THEN 'Not A Triangle' WHEN A + B > C AND A + C > B AND B + C > A THEN 'Scalene' ELSE 'Not A Triangle' END) as type FROM TRIANGLES;
over 4 years ago · Santiago Trujillo Report
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