Image the following lists:
A = [1,2,3,4]
B = ['A','B','C','D']
C = [10,11,12,13]
D = [100,200,300,400]
I should get the following results:
Z = ['1A10100', '2B11200', '3C12300', '4D13400']
I can do this using a lot of empty arrays, do it first using a for loop for A and B than use this new list and append C for each i, etc.
The question is, can this be done in a smarter way. In my real case the lists are 6?
You can use a simple list comprehension:
Z = [''.join(str(x) for x in l) for l in zip(A,B,C,D)]
output: ['1A10100', '2B11200', '3C12300', '4D13400']
If you already have a container for your lists:
lists = [A,B,C,D]
[''.join(str(x) for x in l) for l in zip(*lists)]
Using a list comprehension we can try:
A = [1,2,3,4]
B = ['A','B','C','D']
C = [10,11,12,13]
D = [100,200,300,400]
nums = list(range(0, len(A)))
Z = [str(A[i]) + B[i] + str(C[i]) + str(D[i]) for i in nums]
print(Z) # ['1A10100', '2B11200', '3C12300', '4D13400']
If the length of each lists are fixed and same length you can simply loop by indices, concatenate them, and then push altogether one-by-one into the result array.
A = [1,2,3,4]
B = ['A','B','C','D']
C = [10,11,12,13]
D = [100,200,300,400]
# Prepare the empty array
result = []
# Concat and insert one-by-one
for i in range(len(A)):
result.append('{}{}{}{}'.format(A[i], B[i], C[i], D[i]))
print(result)
Output:
['1A10100', '2B11200', '3C12300', '4D13400']
There are also another way to concatenate and insert to the result array besides the code above:
for i in range(len(A)):
tmp = str(A[i]) + B[i] + str(C[i]) + str(D[i])
result.append(tmp)
for i in range(len(A)):
result.append(f'{A[i]}{B[i]}{C[i]}{D[i]}')