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Jquery to change form action

I have two buttons in a form and two different pages have to be called when they are clicked. when button1 is clicked then page1 must be loaded and when button2 is clicked then page2 must be loaded. i know how to do this in javascript but i have no clue about how to do this in jquery.Can any one help me?

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

Try this:

$('#button1').click(function(){
   $('#formId').attr('action', 'page1');
});


$('#button2').click(function(){
   $('#formId').attr('action', 'page2');
});
over 4 years ago · Santiago Trujillo Report

0

jQuery is just JavaScript, don't think very differently about it! Like you would do in 'normal' JS, you add an event listener to the buttons and change the action attribute of the form. In jQuery this looks something like:

$('#button1').click(function(){
   $('#your_form').attr('action', 'http://uri-for-button1.com');
});

This code is the same for the second button, you only need to change the id of your button and the URI where the form should be submitted to.

over 4 years ago · Santiago Trujillo Report

0

Use jQuery.attr() in your click handler:

$("#myform").attr('action', 'page1.php');
over 4 years ago · Santiago Trujillo Report
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