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jQuery validate plugin on DIV

I am trying to use the validate plugin on a div as shown in the answer to this question:

<script type="text/javascript">
  $("#pseudoForm").validate({
    onfocusout:true,
    rules:{
      first_name:"required",
      last_name:"required"
    }
  });
</script>
<!-- whatever -->
<div id="pseudoForm">
  <input type="text" name="first_name"/>
  <input type="text" name="last_name"/>
</div>

I have all within a form.

I am getting a bunch of different errors on different browsers.

  • Firefox: validator in undefined
  • IE8: 'settings' is null or not an object
  • Chrome: Cannot read property 'settings' of undefined

Any help appreciated!

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

This isn't the answer you want to hear, but the other answer is incorrect (it may have been right when it was posted, but there have been several major jQuery validation plugin changes since then).

The validation plugin is (currently) designed to work on a <form>, and only on a <form>. You can also note that all of the plugin documentation references a form, not any other generic container.

The plugin itself keeps track of validator.currentForm internally, which refers to the this of the passed in selector, getting .elements, etc off that...it's really not going to work any other way, not the way the current version's written.

The overall solution/alternative approach here: call .validate() on the <form> element (the jQuery wrapper for it rather) directly, not any other container. If you need to divide your <form> use <fieldset> elements, possibly using the ignore: ':hidden' option in .validate() if you don't want to validate input fields that aren't visible to the user.

over 4 years ago · Santiago Trujillo Report

0

You're missing a closing bracket. Try this instead:

$("#pseudoForm").validate({
    onfocusout:true,
    rules:{
        first_name:"required",
        last_name:"required"
    }
});
over 4 years ago · Santiago Trujillo Report

0

You can get the same error if you select the form by class

$(".form_class").validate(...

instead of by ID $("#form_id").validate(...

or tag name $("form").validate(...

over 4 years ago · Santiago Trujillo Report
Answer question
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