Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

405
Views
PostgreSQL: Bulk update having unique index

I have a table with unique index on two fields, lane_id and position.

Now, I want to update row using this query:

UPDATE "teams_ticket" SET "position" = ("teams_ticket"."position" + 1) WHERE ("teams_ticket"."lane_id" = 1 AND "teams_ticket"."position" >= 0)

Which ends up with:

duplicate key value violates unique constraint "teams_ticket_position_bfcce9fa_uniq"

If I have more than one ticket.

How can I solve this issue?

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

You need deferrable constraints (and actually defer them, temporally). Deferrable means that the constraints are not checked immediately (say: when the index-tuple is being rewritten) but at the end of the transaction (or statement), when all rows have been updated:

-- \i tmp.sql

CREATE TABLE positions
        ( seq SERIAL PRIMARY KEY
        , position INTEGER NOT NULL UNIQUE DEFERRABLE 
        );

INSERT INTO positions(position)
SELECT generate_series(1,10) gs;

BEGIN;
SET CONSTRAINTS ALL DEFERRED;

update positions
SET position= position +1
WHERE seq <= 6 ;

SELECT * FROM positions ;

UPDATE positions SET position= position +1
WHERE seq > 6
        ;

SELECT * FROM positions ;

UPDATE positions SET position= position +1
        ;

SELECT * FROM positions ;

COMMIT;
over 4 years ago · Santiago Trujillo Report

0

You can use cursor to update them one by one.

DO $$
  DECLARE r record;
BEGIN
  FOR r IN SELECT lane_id, position FROM teams_ticket WHERE lane_id=1 AND position >= 0 ORDER BY position DESC
  LOOP
    UPDATE teams_ticket SET position=position+1 WHERE position=r.position AND lane_id=r.lane_id;
  END LOOP;
END$$;
over 4 years ago · Santiago Trujillo Report

0

You can try

UPDATE teams_ticket t
   SET position = q.position + 1
  FROM (
    SELECT lane_id, position
      FROM teams_ticket
     WHERE lane_id = 1 
       AND position >= 0
     ORDER BY lane_id, position DESC
  ) q 
  WHERE t.lane_id = q.lane_id
    AND t.position = q.position
over 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!