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Cómo implementar el conteo de Oracle (distinto) sobre la partición en Postgres

Aquí está mi muestra de sql en una declaración de selección. La conversión de Oracle a Postgres requiere una forma sencilla de volver a implementar el recuento de Oracle distinto sobre la partición en Postgres.

 , count(distinct on pm.mobseg_state) over (partition by pm.trans_id) as mob_segments_count , count(distinct on pm.country_reg_region_cd) over (partition by pm.trans_id) as countries_count
over 4 years ago · Santiago Trujillo
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Postgres no admite el count(distinct) directamente. Pero puedes implementarlo con una subconsulta:

 select . . ., sum( (seqnum_tm = 1)::int) as mob_segments_count , sum( (seqnum_tr = 1)::int) as countries_count from (select . . ., row_number() over (partition by pm.trans_id, pm.country_reg_region_cd order by pm.country_reg_region_cd) as seqnum_tr, row_number() over (partition by pm.trans_id, pm.mobseg_state order by pm.pm.mobseg_state) as seqnum_tm . . . ) . . .

La idea es sencilla. Calcule row_number() en la partition by claves y la columna distinta. Luego, simplemente sume la cantidad de veces que el valor es "1". Esto requiere una subconsulta, porque no puede anidar funciones de ventana.

over 4 years ago · Santiago Trujillo Report
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