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django error on simple app while run the program

Control is coming to this line and the raising the TypeError:

raise TypeError('view must be a callable or a list/tuple in the case of include().')

TypeError: view must be a callable or a list/tuple in the case of include().

Any help on how to resolve this will be appreciated. Thanks!

over 4 years ago · Santiago Trujillo
1 answers
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0

String reference is not allowed since Django 1.10.

import django.contrib.auth.views

urlpatterns = [
    ...
    url(r'^login/$', django.contrib.auth.views.login, name='login'),
    ...

Change your urls.py code as mention above and it might work.

over 4 years ago · Santiago Trujillo Report
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