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Trim specific leading and trailing characters from a string

I have a string that contains a path

str = "/example/path/with/different/trailing/delimiter\"

and I want to trim the leading and trailing / and \. What is the best practice in Python 3?

Currently I'm using

trimmedPath = str.strip("/\\")
# trimmedPath is "example/path/with/different/trailing/delimiter" as desired

Two questions:

Is this the best trim function for trimming specific characters in Python 3?
Are there specific path functions for such operations in Python 3 so I don't have to set the delimiters manually?

over 4 years ago · Santiago Trujillo

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Example of strip() in action; in this case, removing a leading plus sign:

In [1]: phone_number = "+14158889999"

In [2]: phone_number.strip('+')
Out[2]: '14158889999'

over 4 years ago · Santiago Trujillo Report

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Accepted Answer · 2022-05-27T14:15:52.689Z

I believe strip is the pythonic way. It is usually the case when there is a builtin function.

There are a few builtin path manipulators available in the os library. You might want to use them if one of the manipulators is a match for your use case.

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Trim specific leading and trailing characters from a string

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Andres GPT