python 2.7 code
cStr = '"aaaa","bbbb","ccc,ddd"'
newStr = cStr.split(',')
print newStr # -> ['"aaaa"','"bbbb"','"ccc','ddd"' ]
but, I want this result.
result = ['"aaa"','"bbb"','"ccc,ddd"']
The solution using re.split() function:
import re
cStr = '"aaaa","bbbb","ccc,ddd"'
newStr = re.split(r',(?=")', cStr)
print newStr
The output:
['"aaaa"', '"bbbb"', '"ccc,ddd"']
,(?=") - lookahead positive assertion, ensures that delimiter , is followed by double quote "
Try to use CSV.
import csv
cStr = '"aaaa","bbbb","ccc,ddd"'
newStr = [ '"{}"'.format(x) for x in list(csv.reader([cStr], delimiter=',', quotechar='"'))[0] ]
print newStr
pyparsing has a builtin expression, commaSeparatedList:
cStr = '"aaaa","bbbb","ccc,ddd"'
import pyparsing as pp
print(pp.commaSeparatedList.parseString(cStr).asList())
prints:
['"aaaa"', '"bbbb"', '"ccc,ddd"']
You can also add a parse-time action to strip those double-quotes (since you probably just want the content, not the quotation marks too):
csv_line = pp.commaSeparatedList.copy().addParseAction(pp.tokenMap(lambda s: s.strip('"')))
print(csv_line.parseString(cStr).asList())
gives:
['aaaa', 'bbbb', 'ccc,ddd']