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No se pueden recuperar los datos del formulario serializado de jQuery con la variable PHP $_POST[]

Usando la función Ajax jQuery $.post() , estoy enviando datos de formulario jQuery serialized() a una función PHP que los recibe con éxito en $_POST[] pero las variables individuales $_POST['form_field'] están vacías.

En mi función PHP, print_r($_POST) muestra correctamente los datos del formulario:

 Array ( [action] => send_message [data] => modal_name=olivier&modal_email=olivier%40hotmail.com&modal_message=Hello+world )

Sin embargo, $_POST['modal_name'] , $_POST['modal_email'] y $_POST['modal_message'] están vacíos. ¿Por qué?

HTML:

 <form id='contact'> <input type='text' name='modal_name' id='modal_name' /> <input type='email' name='modal_email' id='modal_email' /> <textarea name='modal_message' id='modal_message'></textarea> </form>

JS:

 $('#contact').on('submit', function(e) { e.preventDefault(); if (modal_name && modal_email && modal_message) { var data = { action: 'send_message', data: $(this).serialize() }; $.post(WPaAjax.ajaxurl, data, function(response) { $('.modal').append(response); }); } });
about 4 years ago · Santiago Trujillo
2 answers
Answer question

0

use $(this).serializeArray() en lugar de $(this).serialize()

Referencia: - https://api.jquery.com/serializeArray/

La diferencia entre ambos:- https://stackoverflow.com/a/10430571/4248328

Tienes que hacer lo siguiente: -

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <form id='contact'> <input type='text' name='modal_name' id='modal_name' /> <input type='email' name='modal_email' id='modal_email' /> <textarea name='modal_message' id='modal_message'></textarea> <input type="submit" value = "submit"> </form> <script type="text/javascript"> $('#contact').on('submit', function(e) { e.preventDefault(); if (modal_name && modal_email && modal_message) { var data = $(this).serializeArray(); data.push({name: 'action', value: 'send_message'}); $.post('query.php', data, function(response) { $('.modal').append(response); }); } }); </script>

Y en php:-

 <?php if(!empty($_POST)){ echo "<pre/>";print_r($_POST); } ?>

Saldrá así: -

 <pre/>Array ( [modal_name] => sdsadsa [modal_email] => a@gmail.com [modal_message] => sadada [action] => send_message )

Nota: - si desea usar serialize() solo, haga lo siguiente: -

 <script type="text/javascript"> $('#contact').on('submit', function(e) { e.preventDefault(); if (modal_name && modal_email && modal_message) { var data = $(this).serialize()+ '&action=send_message'; $.post('query.php', data, function(response) { $('.modal').append(response); }); } }); </script>
about 4 years ago · Santiago Trujillo Report

0

Debería usar $_POST['data']['modal_name'] , $_POST['data']['modal_email'] y $_POST['data']['modal_message'] en su lugar. También use $.serializeArray() de jQuery.

La razón es que envía datos de formulario como param llamado data .

about 4 years ago · Santiago Trujillo Report
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