Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

427
Views
jQuery .when().then() not working as expected

I have an object which acts as a client side API Client which exposes several functions which all return jQuery ajax() objects. Some of those ajax calls have .done() and .fail() calls chained directly onto them because they are actions which need to be taken every time the API responses come back before the rest of the js code is allowed to deal with the response. Pretty standard stuff.

I need to kick off a variable number of API requests, wait for all to fail or succeed, and then continue processing. For the examples I will create, I will simplify this down to just two ajax calls.

So I create an array to hold the returned ajax objects, and then use $.when().apply(null, deferreds).then(function(){//do something after both ajax requests complete}). When the calls complete successfully, everything works great. When calls fail (such as if the ajax call 404s), things are not so great.

The problem is that .then() doesn't seem to detect the fails, even though I thought then() was supposed to be fired regardless of success or failure of the underlying promise(s).

I can switch to .always(), which seems to work better (in that it detects the failures and still triggers the callback) but it seems to fire before some of the .fail() callbacks that are registered directly on the ajax calls, which doesn't make sense to me since I thought the callbacks for an ajax call were called in the order they were registered.

I'm sure I'm just missing something about the behavior of the ajax() when() then() combo.

Fiddle showing successful calls using .then(): https://jsfiddle.net/kwrLyw6q/5/

Fiddle using .then() with failed ajax calls (not working, would love to know why. Seems like this is the "right" way to do it, but I can't figure out where I'm going wrong): https://jsfiddle.net/kwrLyw6q/2/

Fiddle using .always() (working, but notice the out-of-order callback order. At least, out of order compared to the order I want them!): https://jsfiddle.net/kwrLyw6q/7/

about 4 years ago · Santiago Trujillo
1 answers
Answer question

0

It looks like deferred.then() takes three arguments:

  • success function (first argument).
  • fail function (second argument).
  • progress function (third)

updated fiddle

about 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!