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Esta solicitud ha sido bloqueada porque la información confidencial podría divulgarse a sitios web de terceros.

Tengo solicitud de AJAX

Aquí está el código

 <script> $(document).ready(function () { $('#save').click(function () { send_email(); }); }); function send_email() { $.ajax({ url: '/Questions/SendEmail', dataType: "json", type: "GET", contentType: 'application/json; charset=utf-8', async: false, processData: false, cache: false, delay: 15, success: function (result) { alert("Email Forwarded") }, error: function (xhr) { alert('error'); } }); } </script>

Y aquí está el código de back-end

 public JsonResult SendEmail() { SmartSolutions.Models.InvitationMail _objModelMail = new SmartSolutions.Models.InvitationMail(); var emailList = db.InvitationMails.Select(model => model.To); var emailList2 = db.InvitationMails.Select(model => model.Link); var link2 = emailList2.FirstOrDefault(); var emails = String.Join(",", emailList); MailMessage mail = new MailMessage(); mail.To.Add(emails); mail.From = new MailAddress(_objModelMail.From = "suhomlin.eugene93@gmail.com"); mail.Subject = _objModelMail.Subject = "Видео интервью"; string Body = _objModelMail.Body = "Предлагаем пройти интервью" + link2; mail.Body = Body; mail.IsBodyHtml = true; SmtpClient smtp = new SmtpClient(); smtp.Host = "smtp.gmail.com"; smtp.Port = 587; smtp.UseDefaultCredentials = false; smtp.Credentials = new System.Net.NetworkCredential ("***********", "*********");// Enter seders User name and password smtp.EnableSsl = true; smtp.Send(mail); return Json(new { Result = "Success", Message = "Saved Successfully",JsonRequestBehavior.AllowGet}); }

Pero cuando ejecuto la solicitud AJAX, aparece este error

Esta solicitud ha sido bloqueada porque la información confidencial podría divulgarse a sitios web de terceros.

¿Cómo puedo solucionarlo?

over 4 years ago · Santiago Trujillo
1 answers
Answer question

0

Cambio

 return Json(new { Result = "Success", Message = "Saved Successfully",JsonRequestBehavior.AllowGet});

A

 return Json(new { Result = "Success", Message = "Saved Successfully"},JsonRequestBehavior.AllowGet);
over 4 years ago · Santiago Trujillo Report
Answer question
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