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La lectura de datos no funciona en la tabla de estilo CRUD. PHP Ajax, Servidor SQL

Estoy tratando de implementar una tabla en la que puedo agregar datos dinámicamente con ajax, tengo la inserción funcionando y va bien a mi base de datos, pero parece que puedo obtener los datos para mostrarlos en la página.

Estas son mis funciones ajax:

 <script> function saveData(){ var qid = '25'; var ccode = '0123'; var pname = $('#prodName').val(); var pcode = $('#prodCode').val(); var banda = $('#bandA').val(); var nprice = $('#newPrice').val(); $.ajax({ type: "POST", url: "quote2.php?p=add", data: "prodName="+pname+"&prodCode="+pcode+"&bandA="+banda+"&newPrice="+nprice, success: function(data){ viewData(); } }); } function viewData(){ $.ajax({ type: "GET", url: "quote2.php", success: function(data){ $('tbody').html(data); } }); } </script>

Este es mi script php:

 <?php $page = isset($_GET['p'])?$_GET['p']:''; if($page == 'add'){ $quoteID = '25'; $customerCode = '0123'; $productCode = $_POST['prodCode']; $productName = $_POST['prodName']; $bandA = $_POST['bandA']; $nprice = $_POST['newPrice']; $query = "INSERT INTO po_special_price_products (QuoteID, CardCode, SlpCode, SlpName, BandA, NewPrice) VALUES ('$quoteID', '$customerCode', '$productCode', '$productName', '$bandA', '$nprice')"; $stmt = sqlsrv_prepare($sapconn2, $query); if (sqlsrv_execute($stmt) === false) { die(print_r(sqlsrv_errors(), true)); } }else{ $query = "SELECT * FROM po_special_price_products WHERE QuoteID = '$quoteID'"; $stmt = sqlsrv_prepare($sapconn2, $query); $result = sqlsrv_execute($stmt); while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC)){ ?> <tr> <td><?php echo $row['ID'];?></td> <td><?php echo $row['QuoteID'];?></td> <td><?php echo $row['CardCode'];?></td> <td><?php echo $row['SlpCode'];?></td> <td><?php echo $row['SlpName'];?></td> <td><?php echo $row['BandA'];?></td> <td><?php echo $row['NewPrice'];?></td> <td> <button>edit</button> </td> </tr> <?php } } ?>

Pero cuando cargo la página, la tabla está vacía, ¿alguien puede ayudarme?

about 4 years ago · Santiago Trujillo
1 answers
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0

Si entiendo su código php correctamente, debe cambiar esta línea en el script php

 $query = "SELECT * FROM po_special_price_products WHERE QuoteID = '$quoteID'";

a

 if(empty($quoteID) || !isset($quoteID)){ $query = "SELECT * FROM po_special_price_products " } else { $query = "SELECT * FROM po_special_price_products WHERE QuoteID = '$quoteID'"; }
about 4 years ago · Santiago Trujillo Report
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