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ViewsJquery Range Slider with Image Swap
I'm trying to create a range slider that can swap to different images when the user drags the slider. I created a range slider, but i do not know how to take the value of the slider, and then show the corresponding image for the value selected.
Here is a visual example of my goal. 
<input type="range" min="0" max="9" value="0" step="1" onChange="sliderChange(this.value)" />
<br /><br />
slider value = <span id="sliderStatus">0</span>
Any help would be appreciated on how to achieve this.
Thank You
·
Santiago Trujillo
1 answers
Answer question0
var imageUrl = new Array();
imageUrl[0] = 'https://static.pexels.com/photos/39517/rose-flower-blossom-bloom-39517.jpeg';
imageUrl[1] = 'https://static.pexels.com/photos/36764/marguerite-daisy-beautiful-beauty.jpg';
imageUrl[2] = 'http://cdn2.stylecraze.com/wp-content/uploads/2013/07/dahlia-flowers.jpg';
imageUrl[3] = 'https://static.pexels.com/photos/39517/rose-flower-blossom-bloom-39517.jpeg';
imageUrl[4] = 'https://static.pexels.com/photos/36764/marguerite-daisy-beautiful-beauty.jpg';
imageUrl[5] = 'http://cdn2.stylecraze.com/wp-content/uploads/2013/07/dahlia-flowers.jpg';
$(document).on('input change', '#slider', function() {//listen to slider changes
var v=$(this).val();//getting slider val
$('#sliderStatus').html( $(this).val() );
$("#img").prop("src", imageUrl[v]);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="range" id="slider" value="0.0" min="0" max="5" step="1" />
<br /><br />
<img src="" style='width:100px;height:100px;' id='img'/>
slider value = <span id="sliderStatus">0</span>Hope it helps you out.
·
Santiago Trujillo
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