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0

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How to get all elements after selected element

How do I include the last element aswell?

$('div.current').nextUntil("div:last").css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

about 4 years ago · Santiago Trujillo
3 answers
Answer question

0

You could just use nextAll() instead:

$('div.current').nextAll().addClass('foo');
.foo { color: #00F; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

about 4 years ago · Santiago Trujillo Report

0

You could use andSelf method in combination with next() method.

andSelf method adds the previous set of elements on the stack to the current set.

$('div.current').nextUntil("div:last").andSelf().next().css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

about 4 years ago · Santiago Trujillo Report

0

You could use the general sibling combinator ~ in your selector

$('div.current ~ div').css("color", "blue");
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div>First</div>
<div>Second</div>
<div class="current">Third</div>
<div>Fourth</div>
<div>Fifth</div>
<div>Sixth</div>
<div>Seventh</div>

about 4 years ago · Santiago Trujillo Report
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