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Filter array of objects and remove object is filter returns empty values

Here is my question. I have an array of objects as shown below. Each object has a title and rows in it. rows is also array of objects with risk values like P1, P2, P3 etc. I want to filter and get only those rows whose risk is equal to P1. In some objects, there might be no risk with P1 at all. In that case, i want to ignore that object completely.

let data = [ 
    {
        "title": "QA",
        "rows": [
            {
                "risk": "P3",
                "Title": "Permission issue",
            }
        ]
    }, 
    {
        "title": "Prod",
        "rows": [
            {
                "risk": "P5",
                "Title": "Console log errors fix",
            },
            {
                "risk": "P1",
                "Title": "Server is in hung state",
            }
        ]
    }
]

I want the result as follows. As you can see the title QA didnt have P1 at all. so i want to ignore that object as a whole.

    {
        "title": "Prod",
        "rows": [
            {
                "risk": "P1",
                "Title": "Server is in hung state",
            }
        ]
    }
]

I tried using this code. but the problem with this is that the title with QA gets added in the final output even though it doesnot have any P1 risk in it.

let result = input.map((obj) => ({
  ...obj,
  rows: obj.rows.filter((row) => row.risk === "P1"),
}));

Can someone let me know how to filter the objects with P1 and skip the whole object if there are no P1 in it.

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

You can filter out those objects without risk === "P1" by using the function Array.prototype.filter.

const data = [     {        "title": "QA",        "rows": [            {                "risk": "P3",                "Title": "Permission issue",            }        ]    },     {        "title": "Prod",        "rows": [            {                "risk": "P5",                "Title": "Console log errors fix",            },            {                "risk": "P1",                "Title": "Server is in hung state",            }        ]    }],
      result = structuredClone(data).filter(o => {
        o.rows = o.rows.filter(({risk}) => risk === "P1");
        return !!o.rows.length;
      });
      
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

about 4 years ago · Juan Pablo Isaza Report

0

I would skip the map entirely and only use a filter:

const result = data.filter((obj) => {
  let includesP1 = false;
  obj.rows.forEach((r) => {
    if (r.risk === "P1") includesP1 = true;
  });
  return includesP1;
});
about 4 years ago · Juan Pablo Isaza Report

0

You can build up a new list based on those which have rows with P1 risk.

data.reduce((acc, item) => {
  const rows = item.rows.filter(it => it.risk === 'P1');
  if (rows.length === 0) return acc;
  return [...acc, {...item, rows }]
}, [])
about 4 years ago · Juan Pablo Isaza Report
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