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Usando el método de carga de JQuery para representar el componente dentro de un div. Cómo renderizar múltiples componentes en divs

Este es el código que estoy usando. No puedo representar componentes en div con el mismo nombre de clase, pero es extraño, si estoy usando divs, uno con id y otro con clase, se está procesando bien. Si agrego el tercero, no se está renderizando.

 <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8" /> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.6.0/jquery.min.js" integrity="sha256-/xUj+3OJU5yExlq6GSYGSHk7tPXikynS7ogEvDej/m4=" crossorigin="anonymous"></script> <title>React App</title> </head> <body> <div class="team-container"></div> <div id="a" ></div> <div id="b" ></div> <div id="c" ></div> <div id="d" class= "team"></div> <script> function renderComponent(id){ $(document).ready(function () { $(id).load( "private component url link" ); // Handler for .ready() called. }); } //renderComponent("#a") renderComponent("#d") renderComponent(".team-container") </script> </body> </html>
about 4 years ago · Juan Pablo Isaza
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