Although you can break out of a for loop, there are other ways you can be more efficient. More important than breaking out of your loop, is minimizing the most resource heavy processes. Looking at your code, you avoid repetitively appendRow().

Here's a more efficient way to accomplish what you've posted:

// From dataValues, only keep rows that match this criteria:
const filteredValues = dataValues.filter(row => row[11] === 'COMMANDE CONFIRMER' && row[12] !== `` && row[13] === ``)

// If there are rows matching the criteria...
if (filteredValues.length) {

  // Get all indexes of these rows...
  const indexes = filteredValues.map(item => dataValues.findIndex(row => row.every((cell, index) => cell === row[index]))+3)
  // and get each row to only include Columns A - M.
  const values = filteredValues.map(item => item.slice(0, 11))

  // For each index stored...
  indexes.forEach(index => {
    // Clear each row at the appropriate index. (Note: If your cells are not formatted, this can be done more efficiently.)
    copySheet.getRange(`A${index}:M${index}`).clear()
  })

  // Set all values at once.
  pasteSheet.getRange(pasteSheet.getLastRow()+1, 1, values.length, values[0].length).setValues(values)

}

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Uncommented:

const filteredValues = dataValues.filter(row => row[11] === 'COMMANDE CONFIRMER' && row[12] !== `` && row[13] === ``)

if (filteredValues.length) {

  const indexes = filteredValues.map(item => dataValues.findIndex(row => row.every((cell, index) => cell === row[index]))+3)
  const values = filteredValues.map(item => item.slice(0, 11))

  indexes.forEach(index => copySheet.getRange(`A${index}:M${index}`).clear())

  pasteSheet.getRange(pasteSheet.getLastRow()+1, 1, values.length, values[0].length).setValues(values)

}

Browser.msgBox('Commande Confirmer')

Learn More:

• --> Array Methods <--
• Array.length
• Array.filter()
• Array.every()
• Array.map()
• Array.slice()
• Array.forEach()
• Range.setValues()